Advanced Placement (AP), 11.02.2020 22:54, nicog94
The mass of the bullet is 0.01 kg and the mass of the block is 0.99 kg. The bullet is fired into the block andbecomes imbedded in it. The bullet-block combination rises by 0.05 meters. What potential energy is stored inthe pendulum (bullet-block combination)?PE = mgh = a. 50 joules b. 5 joules c. 0.5 joules d. 0.05 joules2. What was the kinetic energy of the pendulum (bullet-block combination) "immediately" after the bullet becameimbedded (i. e. what was the MAXIMUM K. E. of the combination)?KE = PE= (conservation of energy -- no calculation required!) a. 50 joules b. 5 joules c. 0.5 joules d. 0.05 joules3. What was the velocity of the pendulum (bullet-block combination) "immediately" after the bullet becameimbedded (i. e. when its K. E. was maximum)?KE = 1mv2v2 = 2KEv = 2KE = 2 m m a. 0.5 m/sec b. 1.0 m/sec c. 1.5 m/sec d. 2.0 m/s4. What was the momentum of the pendulum (bullet-block combination) "immediately" after the bullet becameimbedded (i. e. when its K. E. was maximum)?p = mv = a. 0 kg m/sec b. 0.25 kg m/sec c. 0.5 kg m/sec d. 1.0 kg m/sec Ballistic Pendulum5/15/082Don RathjenExploratorium Teacher Institute3601 Lyon St., San Francisco, CA [email protected]© 2008 Exploratorium, www. exploratorium5. What was the momentum of the block before the bullet hit it?pblock= mv = (think about this -- mental calculation -- no calculator required!) = a. 0 kg m/sec b. 0.25 kg m/sec c. 0.5 kg m/sec d. 1.0 kg m/sec6. What was the momentum of the bullet before it hit the block?pbullet = (conservation of momentum -- no calculation required!) = a. 0 kg m/sec b. 0.25 kg m/sec c. 0.5 kg m/sec d. 1.0 kg m/sec7. What was the velocity of the bullet before it hit the block (i. e. the "muzzle velocity)?pbullet = mvv = pbullet = m a. 25 m/sec b. 50 m/sec c. 75 m/sec d. 100 m/sec e. 250 m/sec
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The mass of the bullet is 0.01 kg and the mass of the block is 0.99 kg. The bullet is fired into the...
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