Advanced Placement (AP), 18.12.2019 09:31, uticabadgirl

Identify the land, labor, and capital needed to put on a major league baseball game.

you must have at least 10 labor and 10 capital examples.

one suggestion is to visualize all the people you interact with when you go to a game.

remember that capital is human-made things that are used to put on a baseball game.

Answers: 2

Show answers

Answers

answered: KylieAnne

Well let's start with the obvious: the land is the property on which the stadium lies. Team's gotta play somewhere.

Labor being people we must pay to provide the certain services is also an easier one. You want 10 examples so let's rattle 'em off:

We need players to play the game itself. We need managers on the field to set up the batting order, call for shifts, pick our pitcher, etc. We need trainers and medical staff just in case the players get hurt. We need general managers to pick which players are going to play for each team. We need groundskeepers to mow the lawns, lay the bases, pull of the tarp, chalk the dirt, etc. We need cashiers taking tickets of customers at the front.We need police officers and security to make sure people don't get too rowdy and into the game. We need bat boys to field the foul balls and hand them to the sweet children in the good seats. We need people manning the concession stands so I don't have to leave my seat to buy cotton candy and hot dogs. We need some assistants on-hand to bring in the Big League Chew and sunflower seeds (need people to harvest those)... and another product that has to do with "packing a lip" that I'm not sure can be explicitly mentioned here on .

Now for the capital, man-made things used in a baseball game. Even easier than the labor because of how many different things to into the on-field equipment alone:

We need some Louisville Sluggers, don't we? Someone needs to sew jerseys, pants, socks, and hats. Another company is producing cleats.A separate business is producing gloves. We need some man-made machines to mow the lawn. Other man-made machines to make the bases. OTHER man-made machines to chalk the field. Someone is producing pine tar for the bats (and cheating pitchers); it's a chemical process to make; they aren't just finding tree sap. Big League Chew! or any gum brand. That was a Wrigley creation, now I don't know who does it. Let's make the last one a lame one. The tray that they are carrying the snacks on? Yeah, that man-made. We need a lot of those in a stadium of 50,000.

answered: Guest

Answer: the interval on which the curve is concave up is (-∞, -1/2)====== $\displaystyle y = \int_{0}^x \frac{1}{1 + t + t^2} \; dt$ we find the interval where this curve is concave up by finding the interval in which the 2nd derivative is positive.differentiate the curve equation with respect to x $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \end{aligned}$ let the function f denote be the anti-derivative of the inside expression, i.e. a function such that $(d/dx)f(x) = 1/(1 + t + t^2)$ .then use the fundamental theorem of calculus: $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \\& = \frac{d}{dx} \big[ f(x) - f(0) \big] & & \text{\footnotesize apply ftc} \\ & = \frac{d}{dx}f(x) - 0 \\ & = \frac{1}{x + x + x^2} & & \text{\footnotesize since $\frac{d}{dx}f(x) = \frac{1}{1 + x + x^2}$ } \end{aligned}$ differentiate again to get second derivative. we can use chain rule with 1/x as the outside function and 1 + x + x² as the inside function $\begin{aligned} \frac{d}{dx} \left( \frac{dy}{dx} \right) & = \frac{d}{dx}\left(\frac{1}{1 + x + x^2} \right) \\ \frac{d^2y}{dx^2} & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot \tfrac{d}{dx}(1 + x + x^2) \\ & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot (1 + 2x) \\ & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \end{aligned}$ find critical numbers of the second derivative. these numbers are where the 2nd deriv. is undefined or zero.where the 2nd derivative is zero: set (d²y/dx²) to equal 0 and solve for x $\begin{aligned} 0 & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \\ 0 & = -(1+2x) \\ -1 & = 2x \\ x & = -1/2 \end{aligned}$ where the 2nd derivative is undefined: if the denominator is equal to zero, the derivative will be undefeined. attempting to solve the equation 1 + x + x² = 0results in a discriminant of $b^2 - 4ac = 1^2 - 4(1)(1) = -3$ meaning that the equal 1 + x + x² = 0 has no real solutions and therefore will never equal zero.======our only critical number is x = -1/2.this forms two intervals to test the sign for: (-∞, -1/2) and (-1/2, ∞)test values into the 2nd derivative for (-∞, -1/2)if we try x = -1, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = -1} & = \frac{-(1+2(-1))}{\left(1+(-1)+(-1)^2\right)^2} \\ & = \frac{-(1-2)}{1} \\ & = 1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave up on (-∞, -1/2)test values into the 2nd derivative for (-1/2, ∞)if we try x = 0, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = 0} & = \frac{-(1+2(0))}{\left(1+(0)+(0)^2\right)^2} \\ & = \frac{-(1)}{1} \\ & = -1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave down on (-∞, -1/2).the interval on which the curve is concave up is (-∞, -1/2)

answered: Guest

answer; vehicle vin#mileage, a detailed description of work requested, vehicle owner contact phone number;