Two cyclists start at the same point and travel in opposite directions. One cyclist travels 4 mile per hour slower than the other. If the two cyclists are 56 miles apart after 2 hours, what is the rate of each cyclist.?

12 mph and 16 mph

Step-by-step explanation:

distance = speed * time

56 = s * 2 + (s - 4) * 2

56 = 2s + 2s - 8

56 = 4s - 8

64 = 4s

16 = s

s = 16

s - 4 = 12

Let the speed of the faster bike = X

The slower bike would be x - 4 ( 4 mph slower)

Multiply each speed by time and add to equal total distance:

2x + 2(x-4) = 56

Simplify:

2x + 2x -8 = 56

4x -8 = 56

Add 8 to each side:

4x = 64

Divide both sides by 4:

x = 64/4

x = 16

The faster bike rode at 16 miles per hour

The slower bike traveled at 16-4 = 12 miles per hour

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.