Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers. a) When x = −2 and y = 1, is Q(x, y).
a. true
b. false
The hypothesis of Q(−2, 1) is__, which is___. The conclusion is___, which is. Thus Q(−2, 1) is a conditional statement with ahypothesis and aconclusion. So Q(−2, 1) is.
b) Give values different from those in part (a) for which Q(x, y) has the same truth value as in part.
c) Give values different from those in part (c) for which Q(x, y) has the same truth values as in part.

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is is predicate that then . where are rational numbers.

a)

when

Here that is  satisfied. Then

this is wrong. since

That is Thus is false.

b)

Assume .

That is

Here that is this condition is satisfied.

Then

this is not true. since .

This is similar to the truth value of part (a).

Since in both satisfied and for both the points.

c)

if that is and

Here this satisfies the condition .

Then

This also satisfies the condition .

Hence exists and it is true.

d)

Assume

Here satisfies the condition

Then

satisfies the condition .

Thus, point exists and it is true. This satisfies the same values as in part (c)

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: