The mirror in Alan's flashlight is a paraboloid of revolution. If the mirror is 8 centimeters in diameter and 4.5 centimeters deep, where should the light bulb be placed so it is at the focus

of the mirror?

8/9 cm above the Vertex

Step-by-step explanation:

Given that:

Diameter of mirror = 8cm

Depth = 4.5 cm

Assume parabola opens up to the right, then p is positive

y² = 4px

Point on the parabola will then be ;

(Depth, d/2) = (4.5, 4)

x = 4.5 ; y = 4

4² = 4p(4.5)

16 = 18p

p = 16/18

p = 8/9

Hence, bulb should be placed 8/9 cm above the Vertex

1. a^4+8a^3+24a^2+32a+16

2.y^8+8y^7+28y^6+56y^5+70y^4+56y^3+28y^2+8y+1

3.x^6-3x^4y^2+3x^2y^4-y^6

i'm sorry, what's your question here?