The temperature started dropping 0.6 degrees celsius at 2pm. If the temperature is 47.6 degrees celsius at 5pm, what was the beginning temperature at 2 pm?

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The beginning temperature at 2 pm was 49.4 egress Celsius, if the temperature started dropping rate of 0.6 degrees at 2 pm and 47.6 degrees Celsius at 5 pm.

Step-by-step explanation:

The given is,

          Temperature started dropping 0.6 degrees Celsius at 2 pm

          Temperature is 47.6 degrees Celsius at 5 pm

Step:1

          Difference in hours between 2 pm to 5 pm,

                                           = 5 - 2

                                           = 3 hours

Step:2

         Temperature dropping rate = 0.6 degrees Celsius per hour

        Temperature dropped at the 3 hours,

                                                 = Dropping rate × Hours

                                                 = 0.6 × 3

                                                 = 1.8 degrees Celsius

Step:3

        For the beginning of the temperature,

                    (  we need to add the dropped temperature at the end of the temperature value )

       Temperature at 2 pm = Temperature at 5 pm + Dropped Temperature

                                            = 48.6 + 1.8

                                            = 49.4

      Temperature at 2 pm = 49.4  degrees Celsius

Result:

        The beginning temperature at 2 pm was 49.4 egress Celsius, because the temperature started dropping rate of 0.6 degrees at 2 pm and 47.6 degrees Celsius at 5 pm

step-by-step explanation:

which of the following statements correctly describes the expression below based on its degree and number of terms?

314 - 7x2 + 11