Can somebody pls help me out and answer this question properly

x^3 +10x^2 -5x+5

x+8

7x^5+4x^2

Step-by-step explanation:

If the function approaches infinity as x approaches infinity and approaches negativity infinity as x approaches negative infinity then the dominate term is odd and positive

x^3 +10x -5x +5  is both odd and positive

x^3  goes to infinity as x goes to infinity and x^3 goes to negative infinity as x goes to negative infinity

x+8 is both odd and positive

x  goes to infinity as x goes to infinity and x goes to negative infinity as x goes to negative infinity

-2x^5 -x^3 -4x  is odd but negative

-2x^5  goes to  negative infinity as x goes to infinity and -2x^5 goes to  infinity as x goes to negative infinity

-x^3   is odd but negative

-x^3  goes to negative infinity as x goes to infinity and -x^3 goes to infinity as x goes to negative infinity

x^2 +x-3 is even and positive

x^2  goes to  infinity as x goes to infinity and x^2 goes to infinity as x goes to negative infinity

7x^5 +4x^2 is both odd and positive

7x^5  goes to infinity as x goes to infinity and 7x^5 goes to negative infinity as x goes to negative infinity

b

step-by-step explanation:

ez

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.