What is the area of the region between the graphs of f(x)=x^2 + 12 and g(x)=3x^2 + 10 from x=1 to x=4

c is the answer

step-by-step explanation:

if x = 1, then the answer is 3.5

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )