1. what is the equation of the line that contains the point (6, 1) and is perpenuer
whose equation is y = 2x + 1?
a. y = -2x + 1 b. y = -2x + 11 c. y = -4 dy=
=x
+2
what is the equation of the line that contains the point (6,1) and is perpendicular to line whose equation is y=2x+1 ?

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92

it would not be increasing by nothing that i can see probably by 25 percent that is all i can sat\y for now if i have any thing else to say i will edit this.

step-by-step explanation: